Two objects moving along the same straight line are leaving point A with an acceleration a, 2 a & velocity 2 u, u respectively at time t = 0. The distance moved by the object with respect to point A when one object overtakes the other is:
Text Solution
Verified by ExpertsThe correct answer is:
A

Suppose at point B (displacement S) II particle overtakes particle I
For I particle S = (2u) t +
a t 2 .............
For II particle
S = u t +
(2a) t 2 ....................
2ut +
a t 2 = ut +
(2a) t 2
ut =
a t 2
t = 
Putting this value in equation we get
S = 2u ×
+
× a × 
=
+
= 
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